∫x−1x+2dx\int \frac{\sqrt{x-1}}{x+2}dx∫x+2x−1dx
Je délka x=1tcost,y=1tsint,t∈[1,∞)x=\frac{1}{t}\cos t, y=\frac{1}{t}\sin t, t \in [1, \infty)x=t1cost,y=t1sint,t∈[1,∞) konečná?
Lze spojitě dodefinovat f(x,y)=x2y2x2y2+(x−y)2f(x,y)=\frac{x^2y^2}{x^2y^2+(x-y)^2}f(x,y)=x2y2+(x−y)2x2y2
Implicitní y=f(x),x=0,f(0)=π2:arctan(ex−siny)+cos(x−y)=0y=f(x), x=0, f(0)=\frac{\pi}{2}: \arctan(e^x-\sin y) + \cos(x-y)=0y=f(x),x=0,f(0)=2π:arctan(ex−siny)+cos(x−y)=0, najít f′(0),f′′(0)f'(0), f''(0)f′(0),f′′(0)
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