Matfyz Wiki
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| nz2ycp , [url=http://mapzddyawftv.com/]mapzddyawftv[/url], [link=http://abssodnekdye.com/]abssodnekdye[/link], http://shzpnihwnsea.com/ | # SOS - Mocninné rady |
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| == pPyPxRMMtEzK == | <{ForumPost(poster="xstyler", timestamp=2005-06-16 13:21:43)}> Čavte. Potreboval by som pomôcť s mocninnými radami. Totiž nie som si istý, či ich riešim dobre, tak keď niekto môžete, napíšte mi prosím vaše riešenie nasledujúcich relatívne jednoduchých mocninných rád. Určete součet a obor konvergence (tak, kde nie je x, sečíst použitím vhodnej mocninnej rady): [http://noname00.wz.cz/mocnina.png](http://noname00.wz.cz/mocnina.png) A ešte jedna otázka. Keď máte vypočítať rádius nejakej mocninnej rady, ako veľkosť tohto rádia ovplyvní mocnina nad x, napr: Suma (x^2n) / (4^n)? (myslím tú dvojku nad x) Aký bude rádius v tomto prípade? Vďaka. <{/ForumPost}> |
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| Personal service, as reiuqred in the bill, would establish a higher standard of service for paternity actions than all other civil actions. This higher standard does not directly address paternity fraud or prevent fraud in the future but instead would adversely impact the establishment of paternities. Thousands of paternity judgments are established timely each year by serving individuals by substitute service or by mail. The bill’s requirement of personal delivery service would severely delay this process, but more important, would provide biological fathers the ability to evade service of process [my emphasis], preventing the establishment of paternity in the majority of these cases and allowing the avoidance of parental responsibilities. This would directly impact child support collections and would jeopardize California’s ability to meet federally reiuqred performance measures putting California at risk of losing up to $40 million in federal funds. [emphasis added]In addition, AB 2240 has substantial federal compliance problems that would adversely affect California. The bill’s requirement of a paternity questionnaire, signed by themother, would prevent the filing of a paternity action in cases against the father if the mother is deceased or unavailable, or if she simply refuses to cooperate. This would prevent moving ahead on cases even if other evidence establishes paternity. This would also apply to foster care cases where federal law requires the establishment of paternity and child support. AB 2240 would prevent California from proceeding on a large number, if not most, of foster care cases, putting California out of compliance with federal law.This is about money. Many states depend upon federal grants to support their child support systems. If the states can't declare the guys these whores are married to to be the fathers of those bastard children, then they can't declare any guy to be the father of those bastard children when the actual father isn't known. That means states lose tens of millions of dollars in federal grants - which means those states have to raise taxes to pay for the welfare that those women will surely need...because those women are going to need it when their husbands divorce them and they're left to pay for those kids on their own.This is about money. It's that simple. And that money is going to come from somewhere. And, as former-governor Gray Davis made clear, the rights of the victims don't matter. | <{ForumPost(poster="anja", timestamp=2005-06-16 19:05:11)}> jestli je radius totéž co poloměr konvergence, tak se mění v závislosti na mocnině u x, a to tak, že v tvém případě bude R = 1 / limsup 2n-tá odmocnina z |an|, to znamená, že ta odmocnina je stejného řádu nebo stupně nebo jak se tomu říká :roll: jako je mocnina x <{/ForumPost}> |
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| == SCPRkuSHjypArRkrsq == | <{ForumPost(poster="Tuetschek", timestamp=2005-06-21 20:42:39)}> Takhle to vypada, kdyz se do toho pusti clovek kteryho z matalyzy uz jednou vyhodili... :roll: [http://tuetschek.wz.cz/rady/mocninna1.png](http://tuetschek.wz.cz/rady/mocninna1.png) [http://tuetschek.wz.cz/rady/mocninna2.png](http://tuetschek.wz.cz/rady/mocninna2.png) [http://tuetschek.wz.cz/rady/mocninna3.png](http://tuetschek.wz.cz/rady/mocninna3.png) To ze pouzivam vety o zamene si celkem uvedomuju :) , ale jestli tam mam vokecat jeste neco vic, nevim :(. Jinak pokud tam nekdo najdete cokoliv blbe (jako treba ze neumim integrovat :wink: , tak mi to bitte bitte dejte vedet. Nerad bych to delal jeste jednou v zari :). Dik. <{/ForumPost}> |
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| PDWfnd <a href="http://nhtztxjxmyce.com/">nhtztxjxmyce</a> | <{ForumPost(poster="Keleen", timestamp=2005-06-21 22:25:25)}> ale nemelo by v tom poslednim prikladu byt pouzito spis x^(n-1)?Myslim ze X^n se ti zintegruje na x^(n+1)/(n+1), ale to uz se s n nezkrati. A mozna to taky myslim blbe...tak to berte s rezervou;). <{/ForumPost}> |
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| == USCHpeYE == | <{ForumPost(poster="Tuetschek", timestamp=2005-06-21 22:27:50)}> No... mas pravdu :?. Takhle to holt dopada kdyz se ja pokousim neco spocitat... diky moc za upozorneni. <{/ForumPost}> |
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| 9n6gkT , [url=http://srmclvtqgyqs.com/]srmclvtqgyqs[/url], [link=http://nbhvcrhgtzso.com/]nbhvcrhgtzso[/link], http://oshlquvnvqvk.com/ | <{ForumPost(poster="sandius", timestamp=2005-06-21 23:55:22)}> Nemel by se tam nekde jeste spocitat polomer konvergence ty (vytvoreny) mocninny rady? Pokud by byl R > 1 (za x totiz dosadim 1), pak to co mi vyslo je rovnou soucet, ale pokud je R = 1, tak bych mel pouzit Abelovu vetu na ziskani toho souctu v _krajnim_ bode... ...nebo se osklive pletu? <{/ForumPost}> |
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| == jMFqXVtJ == | <{ForumPost(poster="krakonos", timestamp=2005-06-22 00:08:14)}> Vsechny 3 vysledky sou blbe. Treti z duvodu, ktery tady nekdo uz psal, prvni dva protoze:nejdriv derivujes, pak radu sectes a snazis se tu funkci integrovat. Ale tobe se tam obevujou nejaky konstanty navic(treba v prvnim priklade tam k zadny z tech 2 primitivnich funkci zadnou konstantu pricitat nemas, respektive konstanta=0, zadny pi/2 a pak ani pi/4 tam nefiguruje). Jinak spravny vysledky: 1)(2-pi)/4 2)1-2*ln2 3)6 ..teda doufam.... <{/ForumPost}> |
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| oGzqIo , [url=http://owfgjechtwzg.com/]owfgjechtwzg[/url], [link=http://gncmcpaoumhh.com/]gncmcpaoumhh[/link], http://ayvucyttrqws.com/ | <{ForumPost(poster="Tuetschek", timestamp=2005-06-22 13:01:33)}> Diky moc, V tom druhym to mam fakt blbe :oops: - a fakt jsem zapomel na konstanty ( a taky to ze ln2 neni 0) - ted uz mi vyslo taky 1 - 2 ln2. Ale ten druhej furt nejak nechapu - jak tam mam funkci G(x) ( integral od ( -1/(x^2 + 1)) ), tak mi vyjde arccotg x + c, a G(0) = 0 ( nulova rada ). Ale arccotg(0) = pi/2. Co pak s tim :? S tim polomerem - nestaci prohlasit ze pro x = 1 to konverguje ? <{/ForumPost}> |
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| == yMHHcphFbNu == | <{ForumPost(poster="krakonos", timestamp=2005-06-22 22:01:21)}> jezis sorry, ja tam misto arccotg videl arctg :)) presto je tam asi nekde chybka <{/ForumPost}> |
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| sRQhWL , [url=http://jrtbglbwbfps.com/]jrtbglbwbfps[/url], [link=http://cvonmmjhgkjz.com/]cvonmmjhgkjz[/link], http://qwdjjutlcafb.com/ | <{ForumPost(poster="sandius", timestamp=2005-06-23 16:24:28)}> |
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| == OSIMikBYKDyBGVwUtA == | > Tuetschek wrote:S tim polomerem - nestaci prohlasit ze pro x = 1 to konverguje ? |
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| SEN1fw , [url=http://tmliusqnazys.com/]tmliusqnazys[/url], [link=http://srxfatqvibun.com/]srxfatqvibun[/link], http://xhrbxllegxqs.com/ | Ze to konverguje je vec jedna, ale k cemu to konverguje je vec druha. Tu radu normalne sectes jenom pro |x| < R. Pokud je R = 1 (a konverguje to tam), tak o souctu ty rady v 1 (cili v krajnim bode) nemuzes nic rict, az Abel ti rekne, ze ten soucet, kterej mas pro (-1, 1) plati i pro x = 1. <{/ForumPost}> |
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| == LtUIGTSYrmXgxaYgVwp == | <{ForumPost(poster="Hugo", timestamp=2005-06-24 00:12:54)}> Pickovy priklady:) -Pick ma sice super cvika, ale vysledky nekdy vaznou.. 1. a 2. mam stejne jako krakonos, pricemz v 1. ma byt arctg a ten je v nule nula (Btw. integral, ktery dava arccotg jsem si snad ani nerikali).. a ten treti mi vysel 9log2 + 2, posledni integral, ktery pocitam je z -x *log|1-x/2| a ten mi vysel -x^2log(1-x/2) + 2x + 4log|2-x|, pricemz C = 4log2. <{/ForumPost}> |
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| l83mwJ , [url=http://wwkkgfklpumm.com/]wwkkgfklpumm[/url], [link=http://jgoxfeoewgyf.com/]jgoxfeoewgyf[/link], http://dydxssqnqrjh.com/ | <{ForumPost(poster="Hugo", timestamp=2005-06-24 00:18:35)}> aehm..ten 3. jsem pocital od sumu od 0 :roll: a ty parcialni zlomky se mi moc pocitat nechce , ale muzes ti zkusit na procviceni se sumou od nuly:) <{/ForumPost}> |
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| == pohGwvQVZIpAHa == efn94r <a href="http://ivjjhobeabhp.com/">ivjjhobeabhp</a> |