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| # 1. priklad pisomka A <{ForumPost(poster="tibor", timestamp=2005-09-09 17:59:04)}> Ahoj Chcem sa spytat na riesenie 1. prikladu v pisomke A. Vychadza mi ze v x=1 to nema vlastnu limitu a z definicie potom neexistuje Newtonov integral, ale sa mi nechce verit ze by nieco take bolo v pisomke, nemate niekto riesenie? Spocitat neurcity integral nie je problem len co s tym ked x=1. Zadanie je tu [http://www.karlin.mff.cuni.cz/~pick/MAI ... isem_A.pdf](http://www.karlin.mff.cuni.cz/~pick/MAII_04-05_LS_pisem_A.pdf) <{/ForumPost}> <{ForumPost(poster="tutchek", timestamp=2005-09-10 00:25:00)}> pac uz jsem krapet vysel ze cviku, nechal jsem si to spocitat pocitac: \!\(\(-2\)\ \@\(1\/\(\(-1\) + x\)\)\ \@\(\(-1\) + x\)\ \((ArcSin\[\@\(\(-1\) + \ x\)\/\@2] - \@3\ ArcTan\[\@\(\(-1\) + x\)\/\@\(1 - x\/3\)])\)\) uhm... mathematica zas*** -2(ArcSin(SQRT((-1+x)/2)-SQRT(3)*ArcTan(SQRT\[(-1+x)/(1-x/3)])) coz je imho 0 v 1 \[-1 + 1 = 0, zbytek je nezajimavy] ale jsem ted spise ve vodach programovani nez analyzy, takze bez zaruky <{/ForumPost}> <{ForumPost(poster="Ferro_the_King", timestamp=2005-09-10 01:29:07)}> > tutchek wrote: > \!\(\(-2\)\ \@\(1\/\(\(-1\) + x\)\)\ \@\(\(-1\) + x\)\ \((ArcSin\[\@\(\(-1\) + \ > x\)\/\@2] - \@3\ ArcTan\[\@\(\(-1\) + x\)\/\@\(1 - x\/3\)])\)\) A ja myslel, ze kurzy Cinstiny budou az pristi rok :D :D <{/ForumPost}> |