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# 1. priklad pisomka A

<{ForumPost(poster="tibor", timestamp=2005-09-09 17:59:04)}>
Ahoj
  
Chcem sa spytat na riesenie 1. prikladu v pisomke A. Vychadza mi ze v x=1 to nema vlastnu limitu a z definicie potom neexistuje Newtonov integral, ale sa mi nechce verit ze by nieco take bolo v pisomke, nemate niekto riesenie?
  
Spocitat neurcity integral nie je problem len co s tym ked x=1.
  
Zadanie je tu
  
[http://www.karlin.mff.cuni.cz/~pick/MAI ... isem_A.pdf](http://www.karlin.mff.cuni.cz/~pick/MAII_04-05_LS_pisem_A.pdf)
<{/ForumPost}>

<{ForumPost(poster="tutchek", timestamp=2005-09-10 00:25:00)}>
pac uz jsem krapet vysel ze cviku, nechal jsem si to spocitat pocitac:
  
\!\(\(-2\)\ \@\(1\/\(\(-1\) + x\)\)\ \@\(\(-1\) + x\)\ \((ArcSin\[\@\(\(-1\) + \
x\)\/\@2] - \@3\ ArcTan\[\@\(\(-1\) + x\)\/\@\(1 - x\/3\)])\)\)
  
uhm... mathematica zas***
  
-2(ArcSin(SQRT((-1+x)/2)-SQRT(3)*ArcTan(SQRT\[(-1+x)/(1-x/3)]))
  
coz je imho 0 v 1 \[-1 + 1 = 0, zbytek je nezajimavy]
  
ale jsem ted spise ve vodach programovani nez analyzy, takze bez zaruky
<{/ForumPost}>

<{ForumPost(poster="Ferro_the_King", timestamp=2005-09-10 01:29:07)}>

 > tutchek wrote:
 > \!\(\(-2\)\ \@\(1\/\(\(-1\) + x\)\)\ \@\(\(-1\) + x\)\ \((ArcSin\[\@\(\(-1\) + \
 > x\)\/\@2] - \@3\ ArcTan\[\@\(\(-1\) + x\)\/\@\(1 - x\/3\)])\)\)

A ja myslel, ze kurzy Cinstiny budou az pristi rok :D :D
<{/ForumPost}>